B

Step 1: Calculate the heat lost by the copper block.
The mass of the copper block is given as 2.5 kg, which is equivalent to 2500 g.
The specific heat of copper is given as 0.39 J g^-1 K^-1.
The initial temperature of the copper block, T_i, is 500ºC, and the final temperature, T_f, after placing it on ice will be 0ºC.
Using the formula for heat loss:
Q = m imes c imes riangle T
where:
m = mass (2500 g)
c = specific heat (0.39 J g^-1 K^-1)
riangle T = T_i - T_f = 500ºC - 0ºC = 500 K.
Thus:
Q = 2500 g × 0.39 J g^-1 K^-1 × 500 K = 487500 J.

Step 2: Calculate the mass of ice melted.
The latent heat of fusion of water is given as 335 J g^-1.
The mass of ice (m_ice) that can be melted is given by:
m_ice = \frac{Q}{L}
where Q is the heat absorbed by the ice and L is the latent heat of fusion.
Substituting the values:
m_ice = \frac{487500 J}{335 J g^-1} \approx 1455.22 g.

Step 3: Convert the mass of ice into kg.
m_ice \approx 1.455 kg.

Therefore, the maximum amount of ice that can melt is approximately 1.455 kg. Hence, the correct answer option is B.